how to print error in try except python
try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))
                                
                            how to print error in try except python
try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))
                                
                            python catch error and continue
try:
   # Code to test / execute
   print('Test')
except (SyntaxError, IndexError) as E:  # specific exceptions
   # Code in case of SyntaxError for example
   print('Synthax or index error !')
except :
   # Code for any other exception
   print('Other error !')
else:
   # Code if no exception caught
   print('No error')
finally:
   # Code executed after try block (success) or any exception (ie everytime)
   print('Done')
# This code is out of try / catch bloc
print('Anything else')
                                
                            python file open try except error
def FileCheck(fn):
    try:
      open(fn, "r")
      return 1
    except IOError:
      print "Error: File does not appear to exist."
      return 0
result = FileCheck("testfile")
print result
                                
                            python try except continue loop
try:
  #code
except:
  #pass to continue loop or error handling
  pass
else:
  #code
  pass
finally:
  pass
                                
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