python print combinations of string
test_str = "abc"
res = [test_str[i: j] for i in range(len(test_str))
for j in range(i + 1, len(test_str) + 1)]
print(res)#['a', 'ab', 'abc', 'b', 'bc', 'c']python print combinations of string
test_str = "abc"
res = [test_str[i: j] for i in range(len(test_str))
for j in range(i + 1, len(test_str) + 1)]
print(res)#['a', 'ab', 'abc', 'b', 'bc', 'c']python print combinations of string
import itertools
if __name__ == '__main__':
nums = list("ABC")
permutations = list(itertools.permutations(nums))
# Output: ['ABC', 'ACB', 'BAC', 'BCA', 'CAB', 'CBA']
print([''.join(permutation) for permutation in permutations])python combinations function
def combinations(iterable, r):
pool = tuple(iterable)
n = len(pool)
for indices in permutations(range(n), r):
if sorted(indices) == list(indices):
yield tuple(pool[i] for i in indices)python possible combinations
import math
n=7
k=5
print(math.comb(n, k))python combinations
def permutations(iterable, r=None):
# permutations('ABCD', 2) --> AB AC AD BA BC BD CA CB CD DA DB DC
# permutations(range(3)) --> 012 021 102 120 201 210
pool = tuple(iterable)
n = len(pool)
r = n if r is None else r
if r > n:
return
indices = list(range(n))
cycles = range(n, n-r, -1)
yield tuple(pool[i] for i in indices[:r])
while n:
for i in reversed(range(r)):
cycles[i] -= 1
if cycles[i] == 0:
indices[i:] = indices[i+1:] + indices[i:i+1]
cycles[i] = n - i
else:
j = cycles[i]
indices[i], indices[-j] = indices[-j], indices[i]
yield tuple(pool[i] for i in indices[:r])
break
else:
returnall combinations of a string python
import itertools
set = "abcde"
for L in range(0, len(set) + 1)
for subset in itertools.combinations(letters, L): #all combinations in subset
list_comb.append(subset)Copyright © 2021 Codeinu
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