Answers for "how to apply depth first search"

1

depth first search

BFS-> uses queue
DFS-> uses stack or recursion (less code)
NOTE: same idea algo wise for both

IDEA:
1 declare the DS(if bfs-DS will be queue,if dfs-stack)
2 push the start node to DS
3 when you push you mark it as visited
4 until the DS is not empty run a loop
5 inside loop pop the DS(deque for queue or pop for stack) and save it in a new object actual
6 loop through the neighbors of actual
7 if the current neighbor n is not visited
8 then push n in DS
9 mark n as visited in the next line.
Posted by: Guest on April-21-2022
0

depth first search

# Depth First Search: DFS Algorithm

# 1) Pick any node. 
# 2) If it is unvisited, mark it as visited and recur on all its 
#    adjacent (neighbours) nodes. 
# 3) Repeat until all the nodes are visited

graph= {
    'A' : ['B','C'],
    'B' : ['D', 'E'],
    'C' : ['F'],
    'D' : [],
    'E' : ['F'],
    'F' : []
    }
visited = set() # Set to keep track of visited nodes of graph.

def dfs(visited, graph, node):  #function for dfs 
    if node not in visited:
        ''' 
        We start with A
        Then B
        Then D
        Then E
        Then F
        Then C
        A -> B -> D -> E -> F -> C
        '''
        print(node)
        # added to visited to avoid visit the node twice 
        visited.add(node)
        for neighbour in graph[node]:
            ''' 
            * Neighbour of A : B and C but first visit B
            * Then neighbour of B : D and E but first visit D 
            * Then neighbour of D : doesn't have neighbour then backtrack to the neighbour
                of the previous node (B) which is E
            * Then neighbour of E : F
            * Then neighbour of F : doesn't have neighbour then backtrack to the neighbour 
                of the previous node E but doesn't have other neighbour except F which is visited
                So backtracking again to B and B also doesn't have nodes not visited 
                So backtracking again to A: C not visited YAY!
            '''
            dfs(visited, graph, neighbour)
    
print(dfs(visited, graph, 'A'))
Posted by: Guest on January-12-2022

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