Answers for "how to approach insertion sort"

1

insertion sort

def sortNumList(list1):
  x = len(list1)-1
  while True:
    index = 0
    while True:
      if list1[index] > list1[index+1]:
        get = list1[index], list1[index+1]
        list1[index+1], list1[index] = get
        # print(list1[index], list1[index+1])
        index +=1
        if index == x:
          break
          if(all(list1[i] <= list1[i + 1] for i in range(len(list1)-1))):
            break
            return list1
Posted by: Guest on March-19-2022
0

insertion sort

#include <bits/stdc++.h>

using namespace std; 

void insertionSort(int arr[], int n)  
{  
    int i, temp, j;  
    for (i = 1; i < n; i++) 
    {  
        temp = arr[i];  
        j = i - 1;  

        while (j >= 0 && arr[j] > temp) 
        {  
            arr[j + 1] = arr[j];  
            j = j - 1;  
        }  
        arr[j + 1] = temp;  
    }  
}

int main()  
{  
    int arr[] = { 1,4,2,5,333,3,5,7777,4,4,3,22,1,4,3,666,4,6,8,999,4,3,5,32 };  
    int n = sizeof(arr) / sizeof(arr[0]);  

    insertionSort(arr, n);  

    for(int i = 0; i < n; i++){
        cout << arr[i] << " ";
    }

    return 0;  
}
Posted by: Guest on January-16-2021

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