Answers for "quick sort a sorting algorithm"

0

quick sort

def partition(start, end, array):
     
    # Initializing pivot's index to start
    pivot_index = start
    pivot = array[pivot_index]
     
    # This loop runs till start pointer crosses
    # end pointer, and when it does we swap the
    # pivot with element on end pointer
    while start < end:
         
        # Increment the start pointer till it finds an
        # element greater than  pivot
        while start < len(array) and array[start] <= pivot:
            start += 1
             
        # Decrement the end pointer till it finds an
        # element less than pivot
        while array[end] > pivot:
            end -= 1
         
        # If start and end have not crossed each other,
        # swap the numbers on start and end
        if(start < end):
            array[start], array[end] = array[end], array[start]
     
    # Swap pivot element with element on end pointer.
    # This puts pivot on its correct sorted place.
    array[end], array[pivot_index] = array[pivot_index], array[end]
    
    # Returning end pointer to divide the array into 2
    return end
     
# The main function that implements QuickSort
def quick_sort(start, end, array):
     
    if (start < end):
         
        # p is partitioning index, array[p]
        # is at right place
        p = partition(start, end, array)
         
        # Sort elements before partition
        # and after partition
        quick_sort(start, p - 1, array)
        quick_sort(p + 1, end, array)
Posted by: Guest on February-17-2022
0

quick sort

def quicksort(arr):
    if len(arr) <= 1:
        return arr
    pivot = arr[len(arr) // 2]
    left = [x for x in arr if x < pivot]
    middle = [x for x in arr if x == pivot]
    right = [x for x in arr if x > pivot]
    return quicksort(left) + middle + quicksort(right)

print(quicksort([3,6,8,10,1,2,1]))
# Prints "[1, 1, 2, 3, 6, 8, 10]"
Posted by: Guest on February-04-2022

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