Answers for "upload_to a target path using model field instance"

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upload_to a target path using model field instance

def user_directory_path(instance, filename):
    # file will be uploaded to MEDIA_ROOT/user_<id>/<filename>
    return 'user_{0}/{1}'.format(instance.user.id, filename)

class MyModel(models.Model):
    upload = models.FileField(upload_to=user_directory_path)

Posted by: Guest on March-22-2022

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