Answers for "The operator '[]' isn't defined for the type 'Object? Function()'. Try defining the operator '[]'. firebase flutter"

The operator '

List<Brew> _brewListFromSnapshot(QuerySnapshot snapshot) {
    return snapshot.docs.map((document) {
      return Brew(
        name: document['name'] ?? '',
        strength: document['strength'] ?? 0,
        sugars: document['sugars'] ?? '0',
      );
    }).toList();
  }

Posted by: Guest on January-01-1970

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Answers for "The operator '[]' isn't defined for the type 'Object? Function()'. Try defining the operator '[]'. firebase flutter"

Code answers related to "The operator '[]' isn't defined for the type 'Object? Function()'. Try defining the operator '[]'. firebase flutter"

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Answers for "The operator '[]' isn't defined for the type 'Object? Function()'. Try defining the operator '[]'. firebase flutter"

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