greater number in arraya jd
var array = [3 , 6, 2, 56, 32, 5, 89, 32];
var largest= 0;
for (i=0; i<=largest;i++){
if (array[i]>largest) {
var largest=array[i];
}
}
console.log(largest);greater number in arraya jd
var array = [3 , 6, 2, 56, 32, 5, 89, 32];
var largest= 0;
for (i=0; i<=largest;i++){
if (array[i]>largest) {
var largest=array[i];
}
}
console.log(largest);find biggest number in javascript array
var peopleData = [
{ name: "Paul", height: 180, age: 21 },
{ name: "Johnny", height: 198, age: 43 },
{ name: "Brad", height: 172, age: 49 },
{ name: "Dwayne", height: 166, age: 15 }
];
//Find biggest height number
var maxHeight = 0;
for (var i = 0; i < heights.length; i++) {
if (peopleData[i].height > maxHeight) {
maxHeight = peopleData[i].height;
//if you console.log(maxHeight); you should get 198
}
}get largest number in array javascript
const array1 = [1, 3, 2];
Math.max(...array1);
// expected output: 3javascript largest number in array
const max = arr => Math.max(...arr);find highest number in array javascript
function findHighestNumber(nums) {
let inputs = nums.filter((val, i) => nums.indexOf(val) === i)
let max = Math.max(...nums);
let min = Math.min(...nums);
return max + (-min);
}
console.log(difference([1, 7, 18, -1, -2, 9]));find highest number in array javascript
function findHigestNumber(nums) {
let inputs = nums.filter((val, i) => nums.indexOf(val) === i)
let max = inputs.length - 1;
let min = 0;
for(let i = 0; i < inputs.length; i++) {
if(inputs[i] > max) max = inputs[i];
if(inputs[i] < min) min = inputs[i];
}
return max + (-min);
}
console.log(difference([1, 7, 18, -1, -2, 9]));Copyright © 2021 Codeinu
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