Answers for "flask url pass parameter"

4

get arguments from url flask

from flask import request

@app.route(...)
def login():
    username = request.args.get('username')
    password = request.args.get('password')
Posted by: Guest on May-17-2020
1

flask arguments in url

@app.route('/<name>')
def my_view_func(name):
    return name
Posted by: Guest on May-08-2020

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