Answers for "flask uri parameter"

2

flask get with parameters

from flask import request

@app.route('/my-route')
def my_route():
  page = request.args.get('page', default = 1, type = int)
  filter = request.args.get('filter', default = '*', type = str)
Posted by: Guest on May-08-2020
1

flask get with parameters

@app.route('/<name>')
def my_view_func(name):
    return name
Posted by: Guest on May-08-2020

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