Answers for "ascending sort of numbers in javascript"

20

javascript sort by numerical value

// Sort an array of numbers based on numerical value.
let numbers = [23, 65, 88, 12, 45, 99, 2000]

let sortednumbers = numbers.sort((a, b) => a - b);
//=> [12, 23, 45, 65, 88, 99, 2000]
Posted by: Guest on February-28-2020
0

javascript sort numbers descending

var numArray = [140000, 32, 12, 63323, 104, 99];

numArray.sort(function(a, b) {
  return b - a;
});

// Array(6) [ 140000, 63323, 104, 99, 32, 12 ]
Posted by: Guest on January-27-2021
0

sort array of numbers

const myNumbers = [0, 3.14, 2.718, 13];

myNumbers.sort(function (a, b) {
    return a - b;

    /* If a less than b, a negative number will be returned. 
    It means that a is to be placed before b in the final array. For example:

        a = 0, b = 3.14
        a - b = -3.14

    Received a negative number, so a goes before b */
}); 

console.log(myNumbers); // [0, 2.718, 3.14, 13] — correct
Posted by: Guest on December-28-2021

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