Answers for "buscarAmigo(amigos, nombre)"

Javascript

1

buscarAmigo(amigos, nombre)

function buscarAmigo(amigos, nombre) {
  for(let i in amigos) {
    if(i<amigos.length && amigos[i].nombre != nombre) {
      i++;
    } else {
      return amigos[i];
    }
  }
}

Posted by: Guest on March-26-2022

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