Answers for "condition to be leap year"

find leap year

function leapYear(year)
{
  return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
}

Posted by: Guest on April-20-2022

Check if a year is a leap year

if (((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0))
cout<<year<<" is a leap year";
else
cout<<year<<" is not a leap year";

Posted by: Guest on August-21-2021

Code answers related to "condition to be leap year"