find leap year
function leapYear(year)
{
return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
}find leap year
function leapYear(year)
{
return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
}how can you know if a year is a leap year
leapYear = int(input("Input a Year "))
if leapYear %4 == 0:
print("Its a leap year")
else:
print ("Its a normal year")Code to check Check whether a year is leap year or not
<?php
$year = 2022;
if($year % 4 == 0) {
echo $year." is a leap year";
}
else {
echo $year." is a not leap year";
}
?>Copyright © 2021 Codeinu
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