Answers for "await promise all with promise.all"

5

promise.all async await

async function fetchABC() {
  const [a, b, c] = await Promise.all([a(), b(), c()]);

}
Posted by: Guest on April-20-2020
0

promise all in promise all

var arr = [
  {subarr: [1,2,3]},
  {subarr: [4,5,6]},
  {subarr: [7,8,9]}
];
function processAsync(n) {
  return new Promise(function(resolve) {
    setTimeout(
      function() { resolve(n * n); },
      Math.random() * 1e3
    );
  });
}
Promise.all(arr.map(function(entity){
  return Promise.all(entity.subarr.map(function(item){
    return processAsync(item);
  }));
})).then(function(data) {
  console.log(data);
});
Posted by: Guest on November-06-2020

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