Answers for "promise.all await"

5

promise.all async await

async function fetchABC() {
  const [a, b, c] = await Promise.all([a(), b(), c()]);

}
Posted by: Guest on April-20-2020
6

Promise.all

const promise1 = Promise.resolve(3);
const promise2 = 42;
const promise3 = new Promise(function(resolve, reject) {
  setTimeout(resolve, 100, 'foo');
});

Promise.all([promise1, promise2, promise3]).then(function(values) {
  console.log(values);
});
// expected output: Array [3, 42, "foo"]
Posted by: Guest on March-23-2020
0

async await promise all javascript

let characterResponse = await fetch('http://swapi.co/api/people/2/')
let characterResponseJson = await characterResponse.json()
let films = await Promise.all(
  characterResponseJson.films.map(async filmUrl => {
    let filmResponse = await fetch(filmUrl)
    return filmResponse.json()
  })
)
console.log(films)
Posted by: Guest on April-18-2020
0

javascript promise all

var p1 = new Promise((resolve, reject) => { 
  setTimeout(resolve, 1000, "one"); 
}); 
var p2 = new Promise((resolve, reject) => { 
  setTimeout(resolve, 2000, "two"); 
});
var p3 = new Promise((resolve, reject) => {
  setTimeout(resolve, 3000, "three");
});
var p4 = new Promise((resolve, reject) => {
  setTimeout(resolve, 4000, "four");
});
var p5 = new Promise((resolve, reject) => {
  reject("reject");
});

Promise.all([p1, p2, p3, p4, p5]).then(values => { 
  console.log(values);
}, reason => {
  console.log(reason)
});

//From console:
//"reject"

// Evenly, it's possible to use .catch
Promise.all([p1, p2, p3, p4, p5]).then(values => { 
  console.log(values);
}).catch(reason => { 
  console.log(reason)
});

//From console: 
//"reject"
Posted by: Guest on February-26-2020

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