Answers for "jsonconvert.deserializeobject<dynamic>"

C#
2

json.net deserialize dynamic

dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);
Posted by: Guest on May-08-2021
0

json.net deserialize dynamic

dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);
Posted by: Guest on March-23-2022

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