Answers for "vanilla random number generator c#"

C#
63

c# random number

Random rnd = new Random();
int number  = rnd.Next(1, 10);
Posted by: Guest on September-16-2020
10

c# random generator

// One string will be randomly picked and displayed 
Random rnd = new Random();
string[] secOptions = {"string one", "string two", "string three"};
int randomNumber = rnd.Next(0, 3);
string secText = secOptions[randomNumber];
Console.WriteLine(secText);
Posted by: Guest on October-28-2020

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