Answers for "easy random number generator in c# code"

C#
63

c# random number

Random rnd = new Random();
int number  = rnd.Next(1, 10);
Posted by: Guest on September-16-2020
3

random number generator c#

Random numberGen = new Random();
int amountToOutput = 4;
int minimumRange = 1;
int maximumRange = 20;

for(int i = 0; i < amountToOutput; i++)
{
  int randomNumber = numberGen.Next(minimumRange, maximumRange);
  Console.WriteLine(randomNumber);
}
Posted by: Guest on November-19-2020

Code answers related to "easy random number generator in c# code"

C# Answers by Framework

Browse Popular Code Answers by Language