Answers for "random rand = new random() c#"

c# random number

Random rnd = new Random();
int number  = rnd.Next(1, 10);

Posted by: Guest on September-16-2020

c# random number

int random_number = new Random().Next(1, 10) // Generates a number between 1 to 10

Posted by: Guest on October-20-2020

generate a random number in c#

Random rnd = new Random();
int value = rnd.Next(min,max);
Console.Write(value);

Posted by: Guest on July-15-2020

//Создание объекта для генерации чисел
Random rnd = new Random();

//Получить случайное число (в диапазоне от 0 до 10)
int value = rnd.Next(0, 10);

Posted by: Guest on October-18-2021

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