Answers for "randomnumbergenerator c# example"

C#
48

c# random number

Random rnd = new Random();
int number  = rnd.Next(1, 10);
Posted by: Guest on September-16-2020
1

random number generator c#

Random numberGen = new Random();
int amountToOutput = 4;
int minimumRange = 1;
int maximumRange = 20;

for(int i = 0; i < amountToOutput; i++)
{
  int randomNumber = numberGen.Next(minimumRange, maximumRange);
  Console.WriteLine(randomNumber);
}
Posted by: Guest on November-19-2020

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