Answers for "generate random uint c#"

c# random int

Random rnd = new Random();
int number  = rnd.Next(1, 10);

Posted by: Guest on September-16-2020

c# random generator

// One string will be randomly picked and displayed 
Random rnd = new Random();
string[] secOptions = {"string one", "string two", "string three"};
int randomNuber = rnd.Next(0, 3);
string secText = secOptions[randomNuber];
Console.WriteLine(secText);

Posted by: Guest on October-28-2020

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Answers for "generate random uint c#"

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