Answers for "json deserialize attribute c#"

C#
10

deserialize json to object c#

dynamic json = Newtonsoft.Json.JsonConvert.DeserializeObject(jsonstring);
Posted by: Guest on May-02-2020
6

json property C#

public class Videogame
{
    [JsonProperty("name")]
    public string Name { get; set; }

    [JsonProperty("release_date")]
    public DateTime ReleaseDate { get; set; }
}
Posted by: Guest on November-13-2020
1

c# deserialize json

weatherForecast = JsonSerializer.Deserialize<WeatherForecastWithPOCOs>(jsonString);
Posted by: Guest on September-02-2021

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