Answers for "create json object in c#"

create json string c#

//Create my object
        var my_jsondata = new
        {
            Host = @"sftp.myhost.gr",
            UserName = "my_username",
            Password = "my_password",
            SourceDir = "/export/zip/mypath/",
            FileName = "my_file.zip"
        };

        //Tranform it to Json object
        string json_data = JsonConvert.SerializeObject(my_jsondata);

        //Print the Json object
        Console.WriteLine(json_data);

        //Parse the json object
        JObject json_object = JObject.Parse(json_data);

        //Print the parsed Json object
        Console.WriteLine((string)json_object["Host"]);
        Console.WriteLine((string)json_object["UserName"]);
        Console.WriteLine((string)json_object["Password"]);
        Console.WriteLine((string)json_object["SourceDir"]);
        Console.WriteLine((string)json_object["FileName"]);

Posted by: Guest on October-22-2020

Source

create new object from generic c#

return (T)Activator.CreateInstance(typeof(T), new object[] { param });

Posted by: Guest on March-23-2020

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how to create a object in javascript

var a = {
name: "aakash",
  age:30
}

Posted by: Guest on May-16-2020

-1

c# create a json object

dynamic ret = new JObject();

ret = new JObject(new JProperty("vendorDetails", new JObject()));

ret.vendorDetails.Add(new JProperty("vendorName", "Vendor Name"));

Posted by: Guest on April-14-2021

how to add object in dictionary in c#

public TValue this[TKey key]
{
    get
    {
        int index = this.FindEntry(key);
        if (index >= 0)
        {
            return this.entries[index].value;
        }
        ThrowHelper.ThrowKeyNotFoundException();
        return default(TValue);
    }
    set
    {
        this.Insert(key, value, false);
    }
}

Posted by: Guest on April-28-2020

Source

-1

how to create object in php

//define a class
class MyClass{
  //create properties, constructor or methods
}

//create object using "new" keyword
$object = new MyClass();
 
//or wihtout parenthesis
$object = new MyClass;

Posted by: Guest on April-25-2020

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