Without using a new array or the reverse() method to Reverse an Array
var arr = [1, 2, 3, 4];
for (let i = 0; i < Math.floor(arr.length / 2); i++) {
[arr[i], arr[arr.length - 1 - i]] = [arr[arr.length - 1 - i], arr[i]];
}
console.log(arr);Without using a new array or the reverse() method to Reverse an Array
var arr = [1, 2, 3, 4];
for (let i = 0; i < Math.floor(arr.length / 2); i++) {
[arr[i], arr[arr.length - 1 - i]] = [arr[arr.length - 1 - i], arr[i]];
}
console.log(arr);reverse array in a new array
#include <iostream>
#include <iomanip>
using namespace std;
void reverseArray(int array[],int newArray[],int size);
void printArray (int array[],int size);
int main()
{
int list [6],newList[6];
for(int i=0;i<6;i++){
cout<<"Element "<<i<<": ";
cin>>list[i];
}
reverseArray(list,newList,6);
cout<<"Original array: \n";
printArray (list,6);
cout<<endl<<"Reversed array: \n";
printArray (newList,6);
}
void reverseArray(int array[],int newArray[],int size){
for(int i=0,j=size-1;i<size;i++,j--)
newArray[j]=array[i];
}
void printArray (int array[],int size){
for(int i=0;i<size;i++)
cout<<setw(5)<<array[i];
}Copyright © 2021 Codeinu
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