The program must enter a natural number n from the console and find the number previous to n that is not divisible by 2 , 3 and 5 .
#include <bits/stdc++.h>
using namespace std;
//use c++ 17
int main(){
int n;
cin>>n;
for(int i =n-1;;i--){
if(i%2!=0 && i%3!=0 && i%5!=0){
cout<<i;
break;
}
}
return 0;
}Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
